avoid function call to pthread_self in mutex unlock

if the mutex was previously locked, we can assume pthread_self was
already called at the time of locking, and thus that the thread
pointer is initialized.

diff --git a/src/thread/pthread_mutex_unlock.c b/src/thread/pthread_mutex_unlock.c
index 61a2b94..3733788 100644 (file)
--- a/src/thread/pthread_mutex_unlock.c
+++ b/src/thread/pthread_mutex_unlock.c
@@ -3,7 +3,7 @@
 int pthread_mutex_unlock(pthread_mutex_t *m)
 {
        if (m->_m_type != PTHREAD_MUTEX_NORMAL) {
 int pthread_mutex_unlock(pthread_mutex_t *m)
 {
        if (m->_m_type != PTHREAD_MUTEX_NORMAL) {

-               if (m->_m_lock != pthread_self()->tid)
+               if (!m->_m_lock || m->_m_lock != __pthread_self()->tid)

                        return EPERM;
                if (m->_m_type == PTHREAD_MUTEX_RECURSIVE && --m->_m_count)
                        return 0;
                        return EPERM;
                if (m->_m_type == PTHREAD_MUTEX_RECURSIVE && --m->_m_count)
                        return 0;