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bearch: Dump the output requirement and the assigned register in the same line for...
author
Christoph Mallon
<christoph.mallon@gmx.de>
Tue, 27 Nov 2012 22:35:29 +0000
(23:35 +0100)
committer
Christoph Mallon
<christoph.mallon@gmx.de>
Tue, 27 Nov 2012 22:35:29 +0000
(23:35 +0100)
ir/be/bearch.c
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diff --git
a/ir/be/bearch.c
b/ir/be/bearch.c
index
933efca
..
0d669a1
100644
(file)
--- a/
ir/be/bearch.c
+++ b/
ir/be/bearch.c
@@
-278,11
+278,8
@@
void arch_dump_reqs_and_registers(FILE *F, const ir_node *node)
const arch_register_req_t *req = arch_get_irn_register_req_out(node, o);
fprintf(F, "outreq #%u = ", o);
arch_dump_register_req(F, req, node);
- fputs("\n", F);
- }
- for (unsigned o = 0; o < n_outs; ++o) {
const arch_register_t *reg = arch_get_irn_register_out(node, o);
- fprintf(F, "
reg #%u = %s\n", o
, reg != NULL ? reg->name : "n/a");
+ fprintf(F, "
[%s]\n"
, reg != NULL ? reg->name : "n/a");
}
fprintf(F, "flags =");