- for (i = 0; i < preds; ++i) {
- ir_node *n = get_irn_n(node, i);
+ if (is_op_commutative(get_irn_op(node))) {
+ ir_node *l = get_binop_left(node);
+ ir_node *r = get_binop_right(node);
+ int opcode_diff = (int)get_irn_opcode(l) - (int)get_irn_opcode(r);
+
+ if (opcode_diff > 0) {
+ ir_node *t = l;
+ l = r;
+ r = t;
+ } else if (opcode_diff == 0 && l != r) {
+ /* Both nodes have the same opcode, but are different.
+ Need a better method here to decide which goes to the left side. */
+ } /* if */